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A bus travels 1st 150 km is one dimensional motion with 25 km/h what must its last 150 km such that the net average speed for 500 km is 20 km/h |
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Answer» Answer: Explanation: We know that, Speed = Distance / Time So, time taken to travel first 150 km, T1 = Distance / Speed = 150 / 30 = 5 h Time taken to travel next 60 km, t2 = Distance / Speed = 60 / 40 = 1.5 h Total distance TRAVELLED = 210 km Total time taken = t1 + t2 = 5 + 1.5 = 6.5 h So, average speed = Total distance / Total time = 210 / 6.5 = 32.308 km/ |
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