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A bus starts moving with acceleration 2m/s^2. A cyclist 96m behind the bus simultaneously towards the bus at 20m/s. After what time will he be able to overtake the bus? |
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Answer» T=8 seconds.Explanation:It's a fairly simple PROBLEM from KINEMATICS. The problem can be solved by using the following equation.Let the time be 't' for catching the bus20t=96+1/2(2)t^2T= 8 secondsJust UNDERSTAND the concept. What's the total distance to be COVERED by the cyclist is the gap of distance at t=0 and the distance covered by bus in time THope it helps :) |
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