A bus starting from rest moves with a uniform acceleration of 0.1 m/s

1.	A bus starting from rest moves with a uniform acceleration of 0.1 m/s for 2 minutes. Find : (i) the speed acquired, (ii) the distance travelled.
Answer» Correct question:- A bus starting from REST MOVES with UNIFORM acceleration of 0.1m/s² for 2 MINUTES.Find : (i)the speed acquired (ii)the distance travelled Given:- →Initial velocity of the bus=0 →Time taken=2 minutes →Acceleration of the bus=0.1m/s² To find:- →Speed/Velocity acquired(Final velocity) Solution:- Here,we can see that the time is given in minutes,so we shall firstly convert the time into seconds. =>1 minute=60 seconds =>2minutes=2(60) =>120 seconds By using the 1st equation of MOTION,we get:- =>v=u+at =>v=0+(0.1)120 =>v=12m/s Now,by using the 2nd equation of motion,we get:- =>s=ut+1/2at² =>s=0×120+1/2×0.1×(120)² =>s=0.05×120×120 =>s=720m Thus:- →Speed acquired by the bus is 12m/s. →The distance travelled is 720m.

A bus starting from rest moves with a uniform acceleration of 0.1 m/s for 2 minutes. Find : (i) the speed acquired, (ii) the distance travelled.

Answer»

Correct question:-

A bus starting from REST MOVES with UNIFORM acceleration of 0.1m/s² for 2 MINUTES.Find : (i)the speed acquired

(ii)the distance travelled

→Initial velocity of the bus=0

→Time taken=2 minutes

→Acceleration of the bus=0.1m/s²

→Speed/Velocity acquired(Final velocity)

Here,we can see that the time is given in minutes,so we shall firstly convert the time into seconds.

=>1 minute=60 seconds

=>2minutes=2(60)

=>120 seconds

By using the 1st equation of MOTION,we get:-

=>v=u+at

=>v=0+(0.1)120

=>v=12m/s

Now,by using the 2nd equation of motion,we get:-

=>s=ut+1/2at²

=>s=0×120+1/2×0.1×(120)²

=>s=0.05×120×120

=>s=720m

Thus:-

→Speed acquired by the bus is 12m/s.

→The distance travelled is 720m.