rong><U>Answer :

➥ The Speed acquired by a bus = 12 m/s

➥ The Distance TRAVELLED by a bus = 720 m

Given :

➤ Intial velocity of a bus = 0 m/s

➤ Acceleration of a bus = 0.1 m/s²

➤ Time required by the bus = 2 min

To Find :

➤ Speed required by a bus = ?

➤ Distance travelled by a bus = ?

Required Solution :

According to the given question given that Initial velocity of a bus is 0 m/s because the bus STARTING from rest, acceleration is 0.1 m/s² and Time taken by a bus is 2 min.

✒ To find the Speed acuired by a bus and Distance travelled by a bus, first we need to convert the time taken by a bus, minute into second, after that we will find the Speed acuiredquired by a bus and Distance travelled by a bus.

◈ Time taken = 2 min

→ Time taken = 2 × 60

→ Time taken = 120 sec

Now, we have Intial velocity, Acceleration, and Time taken by a bus.

• Intial velocity of a bus = 0 m/s
• Acceleration of a bus = 0.1 m/s²
• Time taken by a bus = 120 sec

We can find Final velocity of a bus by using the first equation of motion which says v = u + at.

Here,

• v is the Final velocity in m/s.
• u is the Intial velocity in m/s.
• a is the Acceleration in m/s².
• t is the Time taken in second.

✎ So let's calculate Final velocity (v) !

⇛ v = u + at

⇛ v = 0 + 0.1 × 120

⇛ v = 0 + 12

⇛ v = 12 m/s

║Hence, Speed acquired by a bus is 12 m/s.║

We can find Distance travelled by a bus by using the second equation of motion which says s = ut + ½ at².

Here,

• s is the distance in m.
• u is the Intial velocity in m/s.
• t is the Time taken in second.
• a is the acceleration in m/s².

✎ So let's find Distance travelled (s) !

⇛ s = ut + ½ at²

⇛ s = 0 × 120 + ½ × 0.1 × 120²

⇛ s = 0 + ½ × 0.1 × 120²

⇛ s = 0 + ½ × 0.1 × 14400

⇛ s = 0 + 1 × 0.1 × 7200

⇛ s = 0 + 1 × 720

⇛ s = 0 + 720

⇛ s = 720 m

║Hence, the Distance travelled by bus is 720 m.║