1.

A bus running at a speed of 18km/h is stopped in2.5seconds by applying breaker. calculate the retardation produced

Answer»

U=18 km/h

= 18\times \frac{1000}{3600}
=5m/S
v=0m/s
t= 2.5s

as we know retardation is NEGATIVE accleration
acceleration =CHANGE in velocity
a =  \frac{v - u}{t}
a =  \frac{0 - 5}{2.5}
a =  \frac{ - 5}{2.5}
a=-2 m/s^2




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