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A bus moving with the velocity of 90 km / he If mass of the bus is 250 kg how much regarding force is applied to stop the bus in 10 second ? Also calculate the distance travelled by the bus at that time. |
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Answer» Initial velocity (u) = 90 km/h = 25 m/sFinal velocity (v) = 0 m/sTime INTERVAL (t) = 10 SMASS of bus (m) = 250 kgTo Find :Retarding Force applied Distance travelled by bus Solution :First we've to find acceleration with which the bus is moving : Acceleration of bus is -2.5 m/s²Negative sign INDICATES that acceleration is applied in opposite direction of motion ________________________________Retarding force applied is : Retarding force applied is -625 NNegative sign indicates force is applied on opposite direction of motion____________________________Distance travelled by bus is : Distance travelled by bus is 125 m |
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