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A bus moving at a speed of 36 m/s is brought to rest in 10 s then find the acceleration and distance travelled by the bus? Write on a nb or page and attach it |
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Answer» ong>ANSWER: -3.6m/s² Explanation: INITIAL velocity of the bus(u)=36m/s Final velocity of the bus(v)=0m/s Time taken to STOP the bus(t)=10sec acceleration = (v-u)/t = (v-u)/t =(0-36)/10 = (v-u)/t =(0-36)/10 = -36/10 = (v-u)/t =(0-36)/10 = -36/10 = -3.6 Hope you like this answer. If you like, please mark this answer as the brainliest and follow me. |
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