1.

A bus moving at a speed of 36 m/s is brought to rest in 10 s then find the acceleration and distance travelled by the bus? Write on a nb or page and attach it​

Answer»

ong>ANSWER:

-3.6m/s²

Explanation:

INITIAL velocity of the bus(u)=36m/s

Final velocity of the bus(v)=0m/s

Time taken to STOP the bus(t)=10sec

acceleration = (v-u)/t

= (v-u)/t =(0-36)/10

= (v-u)/t =(0-36)/10 = -36/10

= (v-u)/t =(0-36)/10 = -36/10 = -3.6

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