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A bus is moving on a straight road with a speed of 126kmh^-1 is brought to rest after 200m. Calculate retardation of the bus. |
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Answer» Use v² = u² + 2AS , where v = 0 , and u = 126km/h * 1000 m/1 km * 1 h/3600 s = 35 m/s and s = 200 m. 0² = (35 m/s)² + 2(200 m) a a = -1225 m²/s² / 400 m = -3.063 m/s². Use v = u + at, where v= 0, u = 35 m/s ,a = -3.063 m/s² 0 = 35 m/s + (-3.063 m/s²)t , t = (-35 m/s) / (-3.063 m/s²) = 11.42 s To verify that this answer AGREES with the EARLIER answer: 0.0032 hours * 3600 s/1 hour = 11.52 s Hope it Helps you ! |
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