iate Question:A bus ACCELERATES uniformly from 100 m/s to 220 m/s in 1 minute. Calculatea) The acceleration of the CAR.b) Distance COVERED by the car in the interval.Answer:Acceleration = 2 m/s²Distance = 9600 mExplanation:As per the provided information in the given question, we have :Initial velocity (u) = 100 m/sFinal velocity (v) = 220 m/sTime (t) = 1 minute = 60 sWe have been asked to calculate acceleration and the distance covered by the car in the interval.❝ Acceleration is nothing the but the rate of change in velocity. ❞ It is a vector quantity and its SI unit is m/s². As I said that acceleration rate of change in velocity. So, we can write in the form of equation,Change is velocity can also be DEFINED as the difference of the final velocity and the initial velocity.Acceleration is denoted by aFinal velocity is denoted by vInitial velocity is denoted by uTime is denoted by TSO,Substitute the value in the formula.∴ The acceleration of the car is 2 m/s².We can calculate the distance travelled easily by using the third equation of motion.Third equation of motion:v denotes final velocityu denotes initial velocitya denotes accelerations denotes distance∴ The distance travelled by the bus is 9600 m.