A bullet was thrown vertically upwards from a height , reaches it's ma

1.	A bullet was thrown vertically upwards from a height , reaches it's maximum height in 4seconds. Calculate the initial velocity of the bullet and the total distance the bullet travels by the time it reaches the maximum height.
Answer» EXPLANATION: initial velocity =? time t = 4 sec g = 10 m/sec^2 by FORMULA v = u- gt v = 0 because BULLET is throughing upward hence 0 = u - 10×4 u = 40 m/ sec now by formula h = ut - 1/2 gt^2 h = 40 ×4 -1/2 10×4^2 = 160 - 80 = 80 meter

A bullet was thrown vertically upwards from a height , reaches it's maximum height in 4seconds. Calculate the initial velocity of the bullet and the total distance the bullet travels by the time it reaches the maximum height.

Answer»

EXPLANATION:

initial velocity =?

time t = 4 sec

g = 10 m/sec^2

by FORMULA v = u- gt

v = 0 because BULLET is throughing upward

hence 0 = u - 10×4

u = 40 m/ sec

now by formula

h = ut - 1/2 gt^2

h = 40 ×4 -1/2 10×4^2

= 160 - 80 = 80 meter

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A bullet was thrown vertically upwards from a height , reaches it's maximum height in 4seconds. Calculate the initial velocity of the bullet and the total distance the bullet travels by the time it reaches the maximum height.

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