A bullet was thrown vertically upwards from a heigh ,reaches it's maxi

1.	A bullet was thrown vertically upwards from a heigh ,reaches it's maximum height in 4seconds calculate the initial velocity of the bullet and the total distance the bullet travels by the time it reaches the maximum height
Answer» Answer: EXPLANATION: t=4seconds during the upward motion u=unknown v=0[finally COMES to rest at maximum height] according to newtons law, v=u+at a=-10[acting DOWNWARDS that is against the motion if the bullet and hence taken as NEGATIVE] 0=u-104 u=40ms^-1 now for the upward motion, v^2-u^2=2as 0-4040=2-10s s=80m for the upward motion therefore the total distance COVERED =2*80m=160m

A bullet was thrown vertically upwards from a heigh ,reaches it's maximum height in 4seconds calculate the initial velocity of the bullet and the total distance the bullet travels by the time it reaches the maximum height

Answer»

Answer:

EXPLANATION:

t=4seconds

during the upward motion

u=unknown

v=0[finally COMES to rest at maximum height]

according to newtons law,

v=u+at a=-10[acting DOWNWARDS that is against the motion if the bullet and hence taken as NEGATIVE]

0=u-10*4

u=40ms^-1

now for the upward motion,

v^2-u^2=2as

0-40*40=2*-10*s

s=80m for the upward motion

therefore the total distance COVERED =2*80m=160m

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A bullet was thrown vertically upwards from a heigh ,reaches it's maximum height in 4seconds calculate the initial velocity of the bullet and the total distance the bullet travels by the time it reaches the maximum height

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