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A bullet of mass 50 gram is fired with a velocity of 100m/s penetrates 10 cm inside the block before coming to rest find the force experienced by the bullet |
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Answer» tion:Mass of bullet= 50g = 0.5kgInitial VELOCITY= 100m/sFinal velocity= 0m/sDistance PENETRATE INSIDE the block= 10cm = 0.1mLet ACCELERATION be aNow,From the 3rd law of motion we know that,2as = v²-u²=>2×a×0.1=0²-100²=>0.2a=-10000=>a. =10000×10/2=>a. = 50000Hence,the acceleration of the bullet is 50000m/sec²Now,As we know that,F=maSo,F=0.5×50000 = 25000N(Solved) |
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