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A bullet of mass 30g is Fired from on of gun 9 kg iF the velocity of bullet is 400m/s then the recoil velocity of the gun will be |
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Answer» Mass of BULLET, m=100g=1000100kg=101kgVelocity of bullet, v=100ms−1Mass of gun, M=20kgLet RECOIL velocity of gun =VBefore firing, the system (gun+bullet) is at rest, THEREFORE, initial momentum of the system =0Final momentum of the system = momentum of bullet + momentum of gun=mv+MV=101×100+20V=10+20VApplying law of conservation of momentum, Final momentum = Initial momentumi.e., 10+20V=020V=−10or V=−2010=−0.5ms−1.Negative sign shows that the direction of recoil velocity of the gun is OPPOSITE to the direction of the velocity of the bullet.Explanation:Plz Mark My Answer As Brainlists |
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