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A bullet of mass 30g is fired from a gun of mass 9kg. if the velocity of the bullet is 400m/s, then the recoil velocity of the gun will be? a) 1.33 m/s in the direction of bulletb) 0.75m/s opposite to the direction of the bulletc) 0.75m/s in the direction of bulletd) 1.33m/s in the opposite direction of the bullet |
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Answer» a BULLET of mass 30g is fired from a gun of mass 9kg. the velocity of the bullet is 400m/s, To Find: the recoil velocity of the gun will be Solution:Recoil velocity is the backward velocity EXPERIENCED by a shooter when shoots a bullet. INITIAL velocity of gun and bullet = 0 u₁ and v₁ are = 0u₁ = Initial velocity of gun = 0u₂ = Initial velocity of bullet = 0mass of gun = m₁ = 9 kg = 9000 gmass of bullet = m₂ = 30 gv₁ = Recoil velocity of gun ( back ward velocity )v₂ = velocity of bullet = 400m/sConservation of momentum :m₁u₁ + m₂u₂ = m₁(-v₁) + m₂v₂( note v₁ is taken as -ve because v₁ is recoil velocity hence backward )=> 9000 * 0 + 30*0 = 9000(-v₁) + 30(400)=> v₁ = 1.33Hence 1.33m/s in the opposite DIRECTION of the bulletLearn More:the RATIO of SI units of Force and momentum is unit of - Brainly.inbrainly.in/question/23969505Two bodies with unequal mass, have equal momentum one has ...brainly.in/question/11911965 |
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