Saved Bookmarks
| 1. |
A bullet of mass 25g moving with a velocity of 500 ms^(-1) enters into a wooden block and comes out of it with a velocity of 100 ms^(-10. Find the work done by the bullet while passing through the wooden block. |
|
Answer» Solution :`m= 25 XX 10^(-3) kg, u= 500m//s, v= 100m//s` Work energy theorem `W= (1)/(2) mv^(2)- (1)/(2) m u^(2)` `=(1)/(2) xx 25 xx 10^(-3) [(100)^(2)- (500)^(2)]= 300J` |
|