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a bullet of mass 20 g moving with speed 200 m/s strikes on a piece of wood and comes to rest in 0.02 s. what is the resistance offered by the wood |
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Answer» gramsinitial velocity = u = 200 m/st = 0.02 sec.let the ACCELERATION or deceleration = a m/sec^2 v = FINAL velocity = u + a t 0 = 200 + a * 0.02 a = - 10, 000 m/sec^2the resistance OFFERED = FORCE against the movement of the bullet = F = m a = 20/1000 kg * 10,000 m/sec^2 = 200 Newtons. |
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