1.

a bullet of mass 2.5 gram moving with a speed of 100 metre per second pierces a bag full of sand keep adjacent to a wall the bullet is stop in the bag after 0.05 second find(1) the acceleration of the bullet(2) force exerted by the send bag on the bullet​

Answer»

Bullet stops - this MEANS that the final VELOCITY of bullet is 0. Here assuming that the DECELERATION is constant, we apply equations of motion.u= 100m/sa=?t= 0.05sv= 0 a= v-u/t = 0-100/0.05= -2000m/s^2F = ma=2.5*10^-3*2*10^3 =-5N



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