A bullet of mass 100g is fired from a gun of mass 20kg with velocity o

1.	A bullet of mass 100g is fired from a gun of mass 20kg with velocity of 100 m per second calculate the velocity of recoil gunplz send m ans.
Answer» ANSWER : The recoil velocity of gun is -0.5 m/s Given : • Mass of bullet = 100 g = 0.1 kg • Mass of gun = 20 kg • Velocity = 100 m/s To Find : • Recoil velocity of the gun = ? Concept Used : To CALCULATE the recoil velocity of gun we need to know the concept of conservation of momentum!! Conservation of Momentum = Mass × Velocity Solution : Hence we conclude that, Momentum(before gun was supposed to be fired) = Momentum of gun + Momentum of bullet Let us assume the recoil velocity of gun as v m/s !! By applying law of conservation of momentum, ★ Conservation of Momentum = Mass × Velocity ➝ 20 + 0.1 kg × 0= 20 × v + 0.1 ×100 ➝ 0 = 20v+ 10 ➝ 0 - 10 = 20v ➝ v = -10/20 ➝ v = -0.5 m/s $\therefore$ The velocity of recoil is -0.5 m/s. Here, the minus sign INDICATES that the gun recoils in the opposite direction to the direction that of the bullet!! ⠀⠀━━━━━━━━━━━━ More to know : • Recoil velocity is the backward velocity . • It is experienced by a SHOOTER when he shoots a bullet. • Hence, it is the RESULT of conservation of momentum . ⠀⠀━━━━━━━━━━━━

A bullet of mass 100g is fired from a gun of mass 20kg with velocity of 100 m per second calculate the velocity of recoil gunplz send m ans.

Answer»

ANSWER :

The recoil velocity of gun is -0.5 m/s

Given :

• Mass of bullet = 100 g = 0.1 kg

• Mass of gun = 20 kg

• Velocity = 100 m/s

To Find :

• Recoil velocity of the gun = ?

Concept Used :

To CALCULATE the recoil velocity of gun we need to know the concept of conservation of momentum!!

Conservation of Momentum = Mass × Velocity

Solution :

Hence we conclude that,

Momentum(before gun was supposed to be fired) = Momentum of gun + Momentum of bullet

Let us assume the recoil velocity of gun as v m/s !!

By applying law of conservation of momentum,

★ Conservation of Momentum = Mass × Velocity

➝ 20 + 0.1 kg × 0= 20 × v + 0.1 ×100

➝ 0 = 20v+ 10

➝ 0 - 10 = 20v

➝ v = -10/20

➝ v = -0.5 m/s

$\therefore$ The velocity of recoil is -0.5 m/s.

Here, the minus sign INDICATES that the gun recoils in the opposite direction to the direction that of the bullet!!

⠀⠀━━━━━━━━━━━━

More to know :

• Recoil velocity is the backward velocity .

• It is experienced by a SHOOTER when he shoots a bullet.

• Hence, it is the RESULT of conservation of momentum .