A bullet of mass 0.02 kg strikes a metal plate of thickness 10 cm with

1.	A bullet of mass 0.02 kg strikes a metal plate of thickness 10 cm with a velocity of 400 m/s and emerge from it with a velocity of 250 m/s. Find the average resistance force offered by the plate to the motion of bullet.
Answer» We know that, v² = u² + 2as a = \(\cfrac{v^2-u^2}{2s}\) a = \(\cfrac{(250)^2-(400)^2}{2\times0.1}\) a = \(\cfrac{62500-160000}{2\times0.1}\) a = \(\cfrac{-97500}{0.2}\) a = -487500 m/s² F = ma F = 0.02 x - 487500 F = -9750 N

A bullet of mass 0.02 kg strikes a metal plate of thickness 10 cm with a velocity of 400 m/s and emerge from it with a velocity of 250 m/s. Find the average resistance force offered by the plate to the motion of bullet.

Answer»

We know that,

v² = u² + 2as

a = \(\cfrac{v^2-u^2}{2s}\)

a = \(\cfrac{(250)^2-(400)^2}{2\times0.1}\)

a = \(\cfrac{62500-160000}{2\times0.1}\)

a = \(\cfrac{-97500}{0.2}\)

a = -487500 m/s²

F = ma

F = 0.02 x - 487500

F = -9750 N

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A bullet of mass 0.02 kg strikes a metal plate of thickness 10 cm with a velocity of 400 m/s and emerge from it with a velocity of 250 m/s. Find the average resistance force offered by the plate to the motion of bullet.

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