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A bullet mass is 15 gm is fired from mass 5 kg with a velocity of 500m calculate the recoil the velocity og the gun and also explain the recoil velocity

Answer»

oil velocity of the rifle is -0.6 m/s. This is a conservation of momentum problem. The explosion of the gunpowder is an internal force allowing us to use the conservation of momentum. Initially the rifle and the bullet are at rest. Σ P 0 = Σ p f 0 = m R v r + m b v b 0 = ( 5 ) ( v r ) + ( 0.015 ) ( 200 ) − 3 = 5 v r v r = − 0.6 m s The negative SIGN TELLS us the rifle moves in the opposite direction of the bullet



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