1.

A bullet (m_(1) = 25 g) is fired with a velocity 400 ms^(-1) get embedded into a bag of sand (m_(2) = 4.9 kg) suspended by a rope. The velocity of the bag is nearly :

Answer»

`0.2 ms^(-1)`
`8 ms^(-1)`
4 `ms^(-1)`
`2 ms^(-1)`

Solution :By CONSERVATION of momentum
`(25)/(100)xx400 = (4.9 +0.025) upsilon`
`upsilon=(10)/(4.925) = 2.030 ~~ 2 mg^(-1)`
(d) is the choice.


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