1.

a bullet 8g fired from a rifle of mass 8kg moves with velocity of 400m/s .find recoil velocity of rifle .​

Answer»

Momentum conservation:

  • As the bullet fired is the result of internal firces inside the gun.
  • No EXTERNAL FORCE during the process.

\implies\rm \vec{F_{ext}} = 0

\implies\rm \dfrac{dp}{dt} = 0

Momentum remain conserved.

Initial Momentum = FINAL Momentum

  • 0 = MV + MV

\to\rm V = \dfrac{-mv}{M}

\to\rm V = \dfrac{-8\times 10^{-3} \times 400}{8}

\to\bf V = 0.4\: (\hat{-i} )\: ms^{-1}

★ So, RECOIL velocity of rifle is 0.4 m/s opposite to the direction of bullet.



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