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A bulb is rated as 250 V; 0.4 A. Find its : (i) power, and (ii) resistance. |
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Answer» V=250v i=0.4A r=v/i r=250/0.4 r=2500/4 resistance=625 ohm p=vi v=250v ,i=0.4a p=(250*0.4)w=100w Hit like if you find it useful |
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