A bulb has a resistance of 20Ω and the p.d across its terminals is V. If the bulb is used for t seconds then energy consumed by the bulb is :(a) (V/20) x t(b) (V2/20) x t(c) V x t = 20(d) (V x t2)/20

A bulb has a resistance of 20Ω and the p.d across its terminals is V

1.	A bulb has a resistance of 20Ω and the p.d across its terminals is V. If the bulb is used for t seconds then energy consumed by the bulb is :(a) (V/20) x t(b) (V2/20) x t(c) V x t = 20(d) (V x t2)/20
Answer» (b) (V²/20) x t V=I × R V=x × 20 Current=V/20 W= I × I × R × t W= v/20 * v/20 * 20 * t = vv/20 t