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A buffer solution contains 0.1 mole of sodium acetate in `1000 cm^(3)` of 0.1 M acetic acid. To the above buffer solutions, 0.1 mole of sodium acetate is further added and dissolved. The pH of the resulting buffer is equal to............A. `pK_(a) - log_(2)`B. `pK_(a)`C. `pK_(a) + 2`D. `pK_(a) + log 2` |
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Answer» Correct Answer - D `pH = pK_(a) + log.(["Salt"])/(["Acid"])` `["Salt"] = (0.1 + 0.1)/(1000 ml) = (0.2)/(1) = 0.2` `["Acid"] = (0.1)/(1000 ml) = (0.1)/(1) = 0.1` `pH = pK_(a) + log 2` `:. pH = 14 - 2 rArr pH = 12`. |
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