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A bubble of air of diameter 0.2 cm rises up uniformly in water with a velocity of 200cm//s . If the density of water is 1gcm^(-3) , find coefficient of viscosity of water. Neglect density of air w.r.t that of water.(g=9.8m//s^(2)) |
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Answer» Solution :`r=(d)/(2)=(0.2)/(2)=0.1cm,v_(t)=-200cm//s` Bubble MOVES upward so it is taken negative `rho_(o)=1(g)/(CM^(3))` `rho=0,eta=?` `v_(t)=(2)/(9)(r^(2)g)/(eta)(rho-rho_(o))` `thereforeeta=(2)/(9)(r^(2)g)/(v_(t))(rho-rho_(0))` `thereforeeta=(2)/(9)(r^(2)g)/(v_(t))(rho-rho_(0))` `=10.9xx10^(-3)` `=0.0109` poise |
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