a boy throws a stone vertically upwards and catches it after time t se

1.	a boy throws a stone vertically upwards and catches it after time t seconds then maximum height reached by it is
Answer» ANSWER: The answer to this QUESTION is Height reached = h = ut/2 + 1/2-9.8t²/4 where u = initial VELOCITY of the stone. I HOPE IT WILL HELP YOU.

a boy throws a stone vertically upwards and catches it after time t seconds then maximum height reached by it is

Answer»

ANSWER:

The answer to this QUESTION is Height reached

= h = ut/2 + 1/2*-9.8*t²/4

where u = initial VELOCITY of the stone.

I HOPE IT WILL HELP YOU.

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a boy throws a stone vertically upwards and catches it after time t seconds then maximum height reached by it is​

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a boy throws a stone vertically upwards and catches it after time t seconds then maximum height reached by it is