1.

A boy standing at a distance of 15m from the bottom of the tower looks the top of the tower at an angle of elevation 30°.Find the height of the tower.draw the figure ​

Answer»

GIVEN that,

BC = 15m

AB = ?

∠B = 30 degree

we know,

AB/BC = TAN 30°

AB/15m = 1/√3

√3×AB = 1×15m

AB = 15m/√3

AB = 3×5/√3

AB = √3×√3×5/√3 ( 3 can be written as √3×√3 = (√3)^2 = 3)

AB = 5√3m

Therefore, the height of the TOWER is 5√3m.

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