1.

A boy runs on a straight road from his home to a market 2.0 km away with a speed of 4 kmh. Finding the market closed, he at once runs back to his home with a speed of 6 km h. Calcualte his(1) average speed (ii) magnitude of average velocity and (iii) average speed of the boy in the timeinterval n(a) 0 to 30 minutes. (b) 0 to 40 minutes.​

Answer»

peed=total dist / total timeTotal distance=2+2=4kmTotal TIME =time home to market +time market to home=2/4+2/60.83Avg speed =4/0.83=4.8kmperhour2)AVG vel=0 since total DISPLACEMENT is 03)in 30 min the boy travelled 2km =4kmperhourIn40 min he travelled 2+1=3kmAvg speed=3/1.5=2kmperhour



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