1.

A boy playing on the roof of a 10 m high building throws a ball with a speed of 10 m/s at an angle of 30° with the horizontal. How far from the throwing point will be ball be at the height of 10 m from the ground ?[g=10ms^(-2),sin30^@=1/2,cos30^@=sqrt(3)/2]

Answer»

8.66 m
5.20 m
4.33 m
2.60 m

Solution :Here `R=(U^(2)sin2theta)/g=((10)^(2)sin60^@)/10`
`5sqrt(3)=8.66m`


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