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A boy and a man carry a uniform pole of length 8 m and of mass 60 kg by supporting it on their shoulders. They are located at the ends of the pole. Where should a load of 90 kg be suspended from boy.s end so that boy carroes only one - third of the total load ? |
Answer» Solution :The mas of pole acts from its centre .C.. Let the load placed at a distance .x. from the BOY.s end.![]() If `N_(1), N_(2)` are the normal REACTIONS on man and boy respectivelt then `N_(1)=(2)/(3)(60+90)g=100 g N` `N_(2)=(1)/(3)(60+90)g=50g N` TAKING turning effects about boy.s end .B., we have. `N_(1)xx8-60g xx 4-90g xx x=0` or `100 g xx 8-60g xx 4-90g xx x =0` on solving x = 6.22 m. |
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