A boxof mass 500 g is moving with a speed of 2.5 ms-1on a table. It comes to a stop after travelling a distance of 2.6 m. Calculate the coefficient of kinetic friction between the box and the table. Take g = 10 ms 2.

A boxof mass 500 g is moving with a speed of 2.5 ms-1on a table. It co

1.	A boxof mass 500 g is moving with a speed of 2.5 ms-1on a table. It comes to a stop after travelling a distance of 2.6 m. Calculate the coefficient of kinetic friction between the box and the table. Take g = 10 ms 2.
Answer» Mass=0.5kg speed=2m/s distance=2.6m use eq. ${v}^{2} - {u}^{2} = 2as$ v=0 -(2.5)^2=2(-a)2.6 a=1.20m/s^2 uN=ma u×(MG)=ma ug=a u=1.20/10 u=0.12 hope it will HELP u. further query ask in COMMENT section

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A boxof mass 500 g is moving with a speed of 2.5 ms-1on a table. It comes to a stop after travelling a distance of 2.6 m. Calculate the coefficient of kinetic friction between the box and the table. Take g = 10 ms 2.

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