ong>Answer:

Height is 3m

Step-by-step explanation:

Area in sq meters sold in the sheet=2820/30=94

Area of rectangular base of the box=20 sq m

If the box is horizontal & h is the height,the area covered by all the 6 sheets=4h+4h+40+5h+5h=94

18H+ 40=94

18h=54

h=3

Height is 3 metres.

If the box is kept vertically,the height becomes 5 mtrs & length & breath of base and top sheets will be 4 mtrs & 3 mtrs,each.

2 example

3 M height.

Total surface area of a box=2[LH+2LB+2BH.(1), where L, B, and H are Length, Breadth, and Height respectively:

assume X M height, then total surface area per equation 1, = 2[(5*X)+(5*4)+(4*X)]…. (2)

however from the total cost and sheet METAL rate, we know the total area as total cost/ cost per square meter,=2820/30=94 sq. Meters

hence equation 2=94, solving for X, we get X=3.

3 example

sheet of metal used for box=2820/30= 94 m

sheet of metal used for top and bottom of box=2*5*4=40 m

sheet of metal used for all 4 sides and height=94–40=54 m

All 4 sides=2(5+4)=18 m

Height=54/18=3 m

4 example

The total surface area of the box is 2820/30 = 94 sq.m.

If the height of the box is h , the surface area of the box is

2 × 5×4 + 2 × 5×h + 2 × 4×h. = 40 +10h + 8h = 18h+40.

Therefore 18h + 40 = 94

Or 18h = 94 - 40 = 54.

Or h = 54/18 =3 m.

Therefore height of the box is 3 meters.

5 example

Total metal used = 2820÷30

I.e. 94m

Metal used in base and top = 2×5×4

I.e. 40m

Remaining metal = 94-40

I.e. 54m

Metal used in sides of the box is = 2×(5+4) (per side)

I.e. 18m

Hence height of the box is 54÷18

I.e 3m

6 example

Total surface area of the CUBOID =2(lb+bh+hl) = 2820/30= 94

here l= 5-m;

b= 4-m

h = ?

So 2(20+4h+5h)= 94

So 9h+20= 47

9h= 27- m

So h= 3- m

Therefore the height of the box = 3- m

7 example

For ₹ 30 ……………..area of metal sheet is 1 sq.m

For ₹ 2820………………………………………………………?

2820/30=94 sq.m

Total surface area of box=2(l×b+b×h+h×l)=94

2(5×4+4×h+h×5)=94

20+9h=47

9h=27

h=27/9=3 m

8 example

Total cost/ rate is area of sheet required.2820/30=94. Less top and bottom of 5x4 size is 40. Balance is 54 sq m. Total 4 sides with height h is 5xh+5xh+4xh+4xh=18h. So height is 54/18=3 mtr

9 example

Total metal used = 2820/30= 94 m

Total surface area= 2(lb+bh+lh)

2(5*4+4h+5h)=94

2(20+9h)=94

40+18h=94

h= 54/18=3 m

10 example

Area of sheet=2820/30=94 sq m

Top & bottom area = 5×4=20sq m

H=(94–20×2)/2/(5+4)=3m

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