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A box contains 50 balls, in which 5 are red balls, 6 are green balls, 9 are blue balls, and the remaining are yellow balls.Quantity I: Probability of picking 2 balls such that one is green and the other one is blueQuantity II: Probability of picking 3 balls such that at least one of them is redQuantity III: Probability of picking 3 balls such that at least one of them is blue1. Quantity III > Quantity I > Quantity II2. Quantity II > Quantity III > Quantity I3. Quantity III > Quantity II > Quantity I4. Quantity I = Quantity II > Quantity III5. Quantity I > Quantity III < Quantity II |
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Answer» Correct Answer - Option 3 : Quantity III > Quantity II > Quantity I Quantity I: Probability of picking 2 tiles such that one is green and the other one is blue ⇒ (6 × 9)/50C2 ⇒ 54/(50 × 49/2) ⇒ 54/1225 ⇒ 0.044 Quantity II: Probability of picking 3 balls such that at least one of them is red ⇒ 1 – 45C3/50C3 ⇒ 1 – (45 × 44 × 43/3)/(50 × 49 × 48/3) ⇒ 1 – (14190/19600) ⇒ 541/1960 ⇒ 0.276 Quantity III: Probability of picking 3 balls such that at least one of them is blue ⇒ 1 – 41C3/50C3 ⇒ 1 – (41 × 40 × 39/3)/(50 × 49 × 48/3) ⇒ 1 – (10660/19600) ⇒ 894/1960 ⇒ 0.456 Quantity III > Quantity II > Quantity I |
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