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A bomb of mass 12kg explodes into two pieces of masses 4 kg and 8 kg. The velocity of 8 kg mass is 6m/s. The kinetic energy of other mass is |
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Answer» USING conservation of momentum We get 0=MV+ mv MV= -mv 8x6 = -4 x v Thus v= -12m/s Then KE =mv^2/2 KE = 4* (12)^2 /2 Then KE = 144*2 Thus KE = 288J |
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