1.

A bomb of mass 12kg explodes into two pieces of masses 4 kg and 8 kg. The velocity of 8 kg mass is 6m/s. The kinetic energy of other mass is

Answer»

USING conservation of momentum

We get

0=MV+ mv

MV= -mv

8x6 = -4 x v

Thus v= -12m/s


Then KE =mv^2/2

KE = 4* (12)^2 /2

Then KE = 144*2

Thus KE = 288J



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