1.

A bomb of 6kg initially at rest explodes into two fragments of masses of 4kg and 2kg respectively.If the greater mass moves with a velocity of 5ms^-1.Find the velocity of the 2kg mass

Answer»

Answer:

10m/s

Explanation:

by LAW of CONSERVATION of MOMENTUM

m1 × V1 = m2 × v2

therefore, 4kg×5m/s=2kg ×(v2)m/s

4×5=2×v2

v2=10m/s



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