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A bomb of 6kg initially at rest explodes into two fragments of masses of 4kg and 2kg respectively.If the greater mass moves with a velocity of 5ms^-1.Find the velocity of the 2kg mass |
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Answer» Answer: 10m/s Explanation: by LAW of CONSERVATION of MOMENTUM m1 × V1 = m2 × v2 therefore, 4kg×5m/s=2kg ×(v2)m/s 4×5=2×v2 v2=10m/s |
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