A bomb of 1 kg is thrown vertically up with speed 100 m/s. After 5 seconds, it explodes into two parts. One of mass 400 gm goes down with speed 25 m/s. What will happen to the other part just afterexplosion.

A bomb of 1 kg is thrown vertically up with speed 100 m/s. After 5 sec

1.	A bomb of 1 kg is thrown vertically up with speed 100 m/s. After 5 seconds, it explodes into two parts. One of mass 400 gm goes down with speed 25 m/s. What will happen to the other part just afterexplosion.
Answer» Solution :After 5 sec, velocity of bomb V = u - gt `= 100-10xx5=50 m//s` `therefore` initial momentum before explosion `= 1xx50 KG ms^(-1)` From momentum conservation, `1xx50=-0.4xx25+0.6 v.` `therefore v.=100 m//s`, upwards.