A bomb at rest at the summit of a cliff breaks into two equal fragments. One of the fragments affains a horizontal velocity of20 sqrt(3)ms^(-1). The horizontal distance between the two fragments, when their displacement vectors is inclined at 60^(@)relative to each other is (g=10ms^(-2))

A bomb at rest at the summit of a cliff breaks into two equal fragment

1.	A bomb at rest at the summit of a cliff breaks into two equal fragments. One of the fragments affains a horizontal velocity of20 sqrt(3)ms^(-1). The horizontal distance between the two fragments, when their displacement vectors is inclined at 60^(@)relative to each other is (g=10ms^(-2))
Answer» `40 sqrt(3)m` `80 sqrt(3)m` `120 sqrt(3)m` `480 sqrt(3)m` ANSWER :D