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a body travels 100m in the first two seconds and 104m in the next 4 seconds. How far it will move in the next 4 seconds if the acceleration is uniform. |
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Answer» Answer: 100=2u+2a u+a=50.......(1) 6u+18a=204...from the FIRST second......(2) solve (1) &(2): u=53 a=-3 In total 10 SEC distance travelled: 10u+1/2 X a x 10x10=380m , putting all the values: so distance covered in next four second=380-204=176m |
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