A body took't' sec. to come down from top of tower. Find the time taken to cover half the height of tower

A body took't' sec. to come down from top of tower. Find the time take

1.	A body took't' sec. to come down from top of tower. Find the time taken to cover half the height of tower
Answer» Solution :Let AB be the TOWER of HEIGHT .h. m and the body taken .t. SECONDS to come down from A to B as shown in the figure . Let C be the midpoint and hence `AC=h/2m` APPLYING the above formula for both the cases, we get `h=1/2"gt"^(2)`...(1)` , h/2=1/2"gt"^(2)`...(2) Eliminating the unconcerned terms by DIVIDING equation (1)by (2), we get `(1)/(2)=h/(h//2)=(1/2"gt"^(2))/(1/2"gt"^(2))rArr 2=(t/t.)^(2)rArr t^(1^(2))=t^(2)/2rArrt^(1)=t/sqrt2s`