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A body thrown vertically up with initial velocity 52 m/s from the ground passes twice a point at 'h' height above at an interval of 10 s. The height 'h' is (g = 10 m/s^2) (1.) 22 m (2.) 10.2 |
| Answer» A body thrown vertically up with initial velocity 52 m/s from the ground passes twice a point at 'h' height above at an interval of 10 s. The height 'h' is (g = 10 m/s^2) (1.) 22 m (2.) 10.2 | |