A body thrown vertically up from the ground passes the height 10.2 m t

1.	A body thrown vertically up from the ground passes the height 10.2 m twice at an interval of 10 sec.Its initial velocity was (g=10m/s?)1) 52 m/s2)26 m/s3) 35 m/s4) 60 m/s
Answer» EXPLANATION: h=10.2m t=10/2=5s g=10m/s^2. u=? h=ut-1/2gt^2 10.2=5u-1/210*25 10.2+125=5u 135.2/5=u u=27m/s

A body thrown vertically up from the ground passes the height 10.2 m twice at an interval of 10 sec.Its initial velocity was (g=10m/s?)1) 52 m/s2)26 m/s3) 35 m/s4) 60 m/s

Answer»

EXPLANATION:

h=10.2m

t=10/2=5s

g=10m/s^2.

u=?

h=ut-1/2*gt^2

10.2=5u-1/2*10*25

10.2+125=5u

135.2/5=u

u=27m/s

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A body thrown vertically up from the ground passes the height 10.2 m twice at an interval of 10 sec.Its initial velocity was (g=10m/s?)1) 52 m/s2)26 m/s3) 35 m/s4) 60 m/s​

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A body thrown vertically up from the ground passes the height 10.2 m twice at an interval of 10 sec.Its initial velocity was (g=10m/s?)1) 52 m/s2)26 m/s3) 35 m/s4) 60 m/s