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A body starts revolving from rest in a circular path of radius 2 m with tangential acceleration a `=2tm//s^(2)`. If its total acceleration at t=2 sec. is `nsqrt(5) m//s^(2)`, then the value of n is: |
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Answer» `v=t^(2)` t=2 `a=sqrt((a_(c))^(2)+(a_(t))^(2))` `rArrsqrt(((v^(2))/(R))^(2)+a_(t^(2)))` `rArrsqrt((8)^(2)+(4)^(2))rArr4sqrt(5)` |
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