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.A body starts from rest with uniform acceleration. Thevelocity of the body after t seconds is v. The displacementof the body in last three seconds is3v (3v |
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Answer» A particle starts from rest so, initial velocity of particle , U = 0 particle acceleration with UNIFORM acceleration a So, particle must follow all kinematical equations . I mean, S = ut + 1/2at² At u = 0, S = 1/2at² Here S is DISPLACEMENT during t time . ∴ displacement in last 2 sec = distance travelled in n sec- distance travelled in (n -2) sec = \bold{S_n-S_{n-1}} = 1/2 an² - 1/2a(n -2)² = 1/2 a (n² - n² + 4n - 4) = a (2n -2) So, displacement in last 2 sec = a(2n - 2) A/C to question, Final velocity = v Time = t Acceleration = a Then, use formula, v = u + at initial rest so, u = 0 v = a × n ⇒a = v/n Now, displacement in last 2 sec = v/n(2n - 2) = 2v - 2v/n |
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