A body starts from rest with an accleration of 6m/s^2 along x axis and 8m/s^2 along y axis.its distance from the origin after 4 sec

A body starts from rest with an accleration of 6m/s^2 along x axis and

1.	A body starts from rest with an accleration of 6m/s^2 along x axis and 8m/s^2 along y axis.its distance from the origin after 4 sec
Answer» s = UT + ½at² u = initial velocity = 0, along x-axis => sₓ = 0t + ½at² = 3(4)² = 48 m (in the +TIVE direction) along y-axis => sᵧ = 0t + ½at² = 4(4)² = 64 m distance from origin = d = √ [(sₓ)² + (sᵧ)² = √ [(48)² + (64)²] = √[6400] = 80 m

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A body starts from rest with an accleration of 6m/s^2 along x axis and 8m/s^2 along y axis.its distance from the origin after 4 sec

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