A body starts accelerating from rest under gravity. What is the displa

1.	A body starts accelerating from rest under gravity. What is the displacement of the body in the time interval of the 10-15 seconds? (Assume g = 10 ms^-2 a. 575 m b. 600 m c. 1000 m d. 625 m
Answer» Answer : D. 625 m Formula for displacement : $S = ut + \frac{1}{2} gt^2\\$ SINCE $u = 0\\$ , $ut = 0$ Displacement of the body in the TIME interval 10-15 SECONDS = $S_{15}-S_{10}$ = $\frac{1}{2}g (15^2 - 10^2)\\ \\\frac{1}{2} (10) (225-100) \\ \\ \frac{1250}{2} \\ \\ 625 m$