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a body start with the initial velocity of 10ms-1 and acceleration 5ms-2 find the distance covered by the 5 sec |
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Answer» USING s=ut+1/2at² s=10×5+1/2×5×5² s=50+1/2×5×25 s=50+1/2×125 s=50+62.5 s=112.5m distance = 112.5m Hope it HELPS:) BRAINLIEST ANSWER PLS |
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