1.

A body rolled on a surface with a speed of 10ms-1 comes to rest after covering a distance of 50m. Find the coefficient of friction. g=10ms-2

Answer»

Answer: The coefficient of FRICTION would be 0.1. It is a dimensionless quantity.


Step-by-step EXPLANATION:

Given that

s=50 m

u=10 m/s

Now, using the third equation of MOTION, we get:

v^2-u^2=2as

Now, putting the values, we get:

0^2-10^2=2*a*50

-100=100a

a= -1

The negative sign of a SHOWS it is retardation.

Now,

F=ma

F=m*1=m

So, the frictional force is m kgms^(-2)

We know,

the formula of force of friction, F= kmg

where k=coefficient of friction, m= mass, and g= ACCELERATION due to gravity.

Now,

F=kmg

Putting the calculated value of F, we get:

m=km*10

k=0.1


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