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A body released from the top of a tower of height H m. After 2s its is stopped and then instantaneously released. What will be its height in 2s |
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Answer» G=V-U/T9.8=0-U/2SECU=4.9m/sUSING SECOND EQUATION OF MOTIONS=UT+1/2AT²A=GS=4.9+1/2×9.8×2²S=4.9+1/2×9.8×4S=4.9+4.9×4S=9.8×4S=3.92 MTRTHE HIEGHT =3.92 METER EXPLANATION:U=INITIAL VELOCITYV=FINAL VELOCITYG=9.8M/SGIVEN:V=0U=?G=9.8T=2 SEC |
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