A body possessing an initial velocity of 2m/s-¹covers a distance of 2 – InterviewSolution

1.

A body possessing an initial velocity of 2m/s-¹covers a distance of 24m during the 6thsecond of its motion calculate the accelerationof the body assuming it to be constant.

Answer»

a=12ms²

Explanation:

s=ut+1/2at²

24m=2m/s×6sec+1/2×a×12

24m=12+1/2×12a

24m=12+12a/2

24m=6+12a

12a=24-6

12a=18

a=18/12

a=3/2ms²

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